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1. SQL / Говнокод #6315

   −856

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   ALTER   PROCEDURE Estimate  @Goods_ID int ,@Workshop_ID int AS
   
   SELECT 9, null, null,  'Арматура',null, null ,  null,  null
   Union
   SELECT     8, dbo.Charges.FK_TypeCh, dbo.Charges.ID, '       '+dbo.Charges.NAME, dbo.Charge_Price.KBO,   
   	             dbo.Charges.Cost, Round(dbo.Charges.Cost*dbo.Charge_Price.KBO,1), 
   		Round( dbo.Charges.Cost*dbo.Charge_Price.KBO/ dbo.Goods.volume,1)
   FROM         dbo.Charge_Price INNER JOIN
                         dbo.Charges ON dbo.Charge_Price.FK_Charge = dbo.Charges.ID INNER JOIN
                         dbo.Workshop ON dbo.Charge_Price.FK_Workshop = dbo.Workshop.ID INNER JOIN
   	        dbo.Goods ON dbo.Charge_Price.FK_Goods= dbo.Goods.ID	
   WHERE     (dbo.Charge_Price.FK_Workshop = 6) AND (dbo.Charge_Price.FK_Goods = @Goods_ID)
   Union
   SELECT     7, null, null,'         Всего  по арматуре', null,   null,Round( SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO) ,1)as Сумма, 
   	Round(SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO/ dbo.Goods.volume),1)
   FROM         dbo.Charge_Price INNER JOIN
   	      dbo.Charges ON dbo.Charge_Price.FK_Charge = dbo.Charges.ID INNER JOIN
                       dbo.Workshop ON dbo.Charge_Price.FK_Workshop = dbo.Workshop.ID INNER JOIN
   	        dbo.Goods ON dbo.Charge_Price.FK_Goods= dbo.Goods.ID	
   WHERE     (dbo.Charge_Price.FK_Workshop = 6) AND (dbo.Charge_Price.FK_Goods = @Goods_ID)
   Union
   /*
     Ещё мурнадцать запросов с объединением
   */
   UNION
   SELECT     -3,  null, null,'         Полная себестоимость',   null, null, Round(SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO)*1.05,1) as Сумма, 
   	Round(SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO/ dbo.Goods.volume)*1.05,1)
   FROM         dbo.Charge_Price INNER JOIN
   	      dbo.Charges ON dbo.Charge_Price.FK_Charge = dbo.Charges.ID INNER JOIN
                       dbo.Workshop ON dbo.Charge_Price.FK_Workshop = dbo.Workshop.ID INNER JOIN
   	        dbo.Goods ON dbo.Charge_Price.FK_Goods= dbo.Goods.ID	
   WHERE    ( (dbo.Charge_Price.FK_Workshop = @Workshop_ID)  OR  (dbo.Charge_Price.FK_Workshop = 6)   OR
   		 (dbo.Charge_Price.FK_Workshop = 7) )AND (dbo.Charge_Price.FK_Goods = @Goods_ID) 
   UNION 
   SELECT     -4,  null, null,'         Плановые накопления',   null, null, Round(SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO)*0.1575,1) as Сумма, 
   	Round(SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO/ dbo.Goods.volume)*0,1575,1)
   FROM         dbo.Charge_Price INNER JOIN
   	      dbo.Charges ON dbo.Charge_Price.FK_Charge = dbo.Charges.ID INNER JOIN
                       dbo.Workshop ON dbo.Charge_Price.FK_Workshop = dbo.Workshop.ID INNER JOIN
   	        dbo.Goods ON dbo.Charge_Price.FK_Goods= dbo.Goods.ID	
   WHERE    ( (dbo.Charge_Price.FK_Workshop = @Workshop_ID)  OR  (dbo.Charge_Price.FK_Workshop = 6)   OR
   		 (dbo.Charge_Price.FK_Workshop = 7) )AND (dbo.Charge_Price.FK_Goods = @Goods_ID) 
   UNION
   SELECT     -5,  null, null,'         Цена оптовая',   null, null, Round(SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO)*1.2075,1) as Сумма, 
   	Round(SUM( dbo.Charges.Cost*dbo.Charge_Price.KBO/ dbo.Goods.volume)*1,2075,1)
   FROM         dbo.Charge_Price INNER JOIN
   	      dbo.Charges ON dbo.Charge_Price.FK_Charge = dbo.Charges.ID INNER JOIN
                       dbo.Workshop ON dbo.Charge_Price.FK_Workshop = dbo.Workshop.ID INNER JOIN
   	        dbo.Goods ON dbo.Charge_Price.FK_Goods= dbo.Goods.ID	
   WHERE    ( (dbo.Charge_Price.FK_Workshop = @Workshop_ID)  OR  (dbo.Charge_Price.FK_Workshop = 6)   OR
   		 (dbo.Charge_Price.FK_Workshop = 7) )AND (dbo.Charge_Price.FK_Goods = @Goods_ID) 
   
   Order by 1 desc, 2, 3

   Формирование какой то сметы в стле 1С

   dens, 12 Апреля 2011

   Комментарии (8)

2. SQL / Говнокод #6288

   −855

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   SELECT h.*,
   			      if(h.gender_id != 0, (SELECT g.title FROM p_cm5_horses_gender g WHERE h.gender_id = g.id AND h.lang_id = g.lang_id),"") AS gender,
   			        if(h.colour_id != 0, (SELECT c.title FROM p_cm5_horses_colour c WHERE h.colour_id = c.id AND h.lang_id = c.lang_id),"") AS colour,
   			        if(h.color_group != 0, (SELECT cg.title FROM p_cm5_horses_colour_group cg WHERE h.color_group = cg.id AND h.lang_id = cg.lang_id),"") AS color_group_name,
   			        if(h.temper_id != 0, (SELECT t.title FROM p_cm5_horses_temper t WHERE h.temper_id = t.id AND h.lang_id = t.lang_id),"") AS temper,
   			        if(h.grading_id != 0, (SELECT t.title FROM p_cm5_horses_grading t WHERE h.temper_id = t.id AND h.lang_id = t.lang_id),"") AS grading,
   			        if(h.breed_id != 0, (SELECT b.title FROM p_cm5_horses_studbook b WHERE h.breed_id = b.id AND h.lang_id = b.lang_id),"") AS breed,
   			        if(h.training_first != 0, (SELECT t.training_name FROM p_cm5_horses_training t WHERE h.training_first = t.id AND h.lang_id = t.lang_id),"") AS training_first_name,
   			        if(h.level_first != 0, (SELECT t.level_name FROM p_cm5_horses_training_level t WHERE h.level_first = t.id AND h.lang_id = t.lang_id),"") AS level_first_name,
   			        if(h.training_second != 0, (SELECT t.training_name FROM p_cm5_horses_training t WHERE h.training_second = t.id AND h.lang_id = t.lang_id),"") AS training_second_name,
   			        if(h.level_second != 0, (SELECT t.level_name FROM p_cm5_horses_training_level t WHERE h.level_second = t.id AND h.lang_id = t.lang_id),"") AS level_second_name,
   			        if(h.price_id != 0, (SELECT p.title FROM p_cm5_horses_price p WHERE h.price_id = p.id AND h.lang_id = p.lang_id),"") AS price,
   			        if(h.price_id != 0, (SELECT p.title FROM p_cm5_horses_price p WHERE h.price_id = p.id AND p.lang_id = 2),"") AS price2
   			        FROM p_cm5_horses h
   			        WHERE h.enabled = 1 AND h.lang_id = 1 AND h.id = 219

   копался в одном проекте который нам отдали на аутсорс, нашел своего рода LEFT JOIN-ины

   fosco, 08 Апреля 2011

   Комментарии (2)

3. SQL / Говнокод #6242

   −855

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   ALTER  TRIGGER Snag ON [dbo].[Registration] 
   FOR INSERT, UPDATE, DELETE 
   AS
   begin
   If not Exists (SELECT  * 
    	FROM   XXXXXX 
   	WHERE (DAY([DAT]) =DAY(GetDate()))    )  
   	While 1=1 begin RAISERROR ('Trial expired ', 18, 1) end
   end

   trial period control :)

   dens, 06 Апреля 2011

   Комментарии (5)

4. SQL / Говнокод #6234

   −864

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   SELECT COUNT(*) FROM apteka.cache_offers WHERE ORG_ID = '21963' AND `subject_id` IN (35,30052,20262,20263,20001,30488,30776,22099,22044,21982,21938,21823,
   (еще триста чисел),
   26313,26358,26478,23381,27430,26367,26418,23433,23404,23372,23289,23321,23285,23315,23282,23406,23287,
   26356,23429,23263,23349,23399,23356,23291,23346,23351,23250,23198,23194,23319,23238,23296,23259,23167,23268,23130,23052,23119,22430,23146,22315,23069,23083,23
   127,23189,23023,23014,23059,22988,23020,23007,22989,22949,22937,22939,22941,22979,22786,22842,22849,22758,22913,22919,22833,22718,22753,22779,22724,22857,2276
   8,22761,22733,22823,22759,22764,22658,22681,22674,22706,22599,22698,22667,22627,22776,22654,22655,22601,22619,22598,22694,22696,22603,22541,22570,22469,22534,
   22515,22676,22516,22477,22491,22677,22513,22421,22537,22451,22507,22482,22440,22353,22523,22422,22510,22397,22473,22348,22383,22424,22333,22380,22359,22508,22
   486,22456,22330);

   Стандартный запрос. При формировании страницы конструкция встречается многократно (>10 раз)

   deadwire, 05 Апреля 2011

   Комментарии (24)

5. SQL / Говнокод #6226

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   USE [VOLTAREN]
   GO
   /****** Object:  UserDefinedFunction [dbo].[myReplace]    Script Date: 04/05/2011 12:11:42 ******/
   SET ANSI_NULLS ON
   GO
   SET QUOTED_IDENTIFIER ON
   GO
   ALTER FUNCTION [dbo].[myReplace](@NAME varchar(255))
   RETURNS varchar(255)
   BEGIN
   set @NAME = (
   	UPPER(
   replace(
   	replace(
   		replace(
   			replace(
   				replace(
   					replace(
   						replace(
   							replace(
   								replace(
   									replace(
   										replace(
   											replace(
   												replace(
   													replace(
   														replace(
   															replace(
   																replace(
   																	replace(
   																		replace(
   																			replace(
   																				replace(
   																					replace(
   																						replace(
   																							replace(
   																								replace(
   																									replace(
   																										replace(
   																											replace(
   																												replace(
   																													replace(
   																														replace(
   																															replace(
   																																replace(
   																																	replace(
   																																		replace(
   																																			replace(
   																																				@NAME,'*','')
   																																			,'табл','таб')
   																																		,'~','')
   																																	,'`','')
   																																,'<','')
   																															,'>','')
   																														,'}','')
   																													,'{','')
   																												,']','')
   																											,'[','')
   																										,'=','')
   																									,'_','')
   																								,'#','')
   																							,'$','')
   																						,'?','')
   																					,'^','')
   																				,'&','')
   																			,'@','')
   																		,'''','')
   																	,'"','')	
   																,':','')
   															,'%','')
   														,'-','')
   													,'+','')
   												,')','')
   											,'(','')
   										,'N','')
   									,'№','')
   								,'|','')
   							,'\','')
   						,'/','')
   					,'!','')
   				,';','')
   			,',','')
   		,'.','')
   	,' ','')));
   	
   
   return(
   replace(
   	@NAME,
   'покробол','по')
   )
   	
   
   END;

   функция удаления не нужных символов из строки

   cu3blukekc, 05 Апреля 2011

   Комментарии (26)

6. SQL / Говнокод #6218

   −858

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   create or replace function t8() returns integer as $$
   declare
       rec record;
   begin
       for rec in select * from purchase loop
         update purchase set amount=(
                 select book.cost*purchase.quantity*(1-customer.discount/100.0)
                 from purchase, book, customer
                 where purchase.id=rec.id and
                     book.id=purchase.book and
                     customer.id=purchase.customer
         )
         where purchase.id=rec.id;
       end loop;
   
       return 1;
   end;
   $$ language plpgsql;
   
   select t8();

   прочно засевшие в голове алгоритмические языки

   ilardm, 04 Апреля 2011

   Комментарии (2)

7. SQL / Говнокод #6177

   −861

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   if @new_dg_sor_code is null and @dg_sor_code<>7
   and
   (
   	(
   		(select count(*) from tbl_dogovorlist WITH (nolock) where dl_dgcod=@dg_code and dl_svkey in (1,1158,1166) and dl_control=0)=
   		(select count(*) from tbl_dogovorlist WITH (nolock) where dl_dgcod=@dg_code and dl_svkey in (1,1158,1166))
   	)
   	and (
   		(select count(*) from tbl_dogovorlist WITH (nolock) where dl_dgcod=@dg_code and dl_svkey=3 and dl_control=0)=
   		(select count(*) from tbl_dogovorlist WITH (nolock) where dl_dgcod=@dg_code and dl_svkey=3)
   	)
   	and (
   		(select count(*) from tbl_dogovorlist WITH (nolock) where dl_dgcod=@dg_code and dl_svkey=5 and dl_control=0)=
   		(select count(*) from tbl_dogovorlist WITH (nolock) where dl_dgcod=@dg_code and dl_svkey=5)
   	)
   )

   Видимо зарплата этого парня зависит от количества запросов к tbl_dogovorlist.
   А иначе зачем ему 6 запросов вместо одного?

   Anatoly, 01 Апреля 2011

   Комментарии (4)

8. SQL / Говнокод #6148

   −862

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   BEGIN
       DECLARE @id_user int;
       IF (EXISTS(SELECT ut.id_user FROM project_userTable ut WHERE ut.userStr=@UserName OR ut.email = @email))
           begin
               SET @errors='Такое имя или пароль уже существуют';
               RETURN;
           end
       INSERT INTO project_userTable (userStr,passwordStr,email,profileLink,id_user_type,activate_ticket)
       VALUES (@UserName,@password, @email, @profileLink,2,@activate_ticket)
       IF (@@ROWCOUNT!=1)
       begin
           SET @errors='Ошибка регистрации';
           RETURN
       end
       SET @id_user=@@IDENTITY;
       INSERT INTO project_keyTable ([datetime],id_user, first_key ,second_key )
       VALUES (GETDATE(),@id_user,@firstKey,@secodKey)
       IF (@@ROWCOUNT=1)
       begin
           SET @errors='Done';
           RETURN
       end
       SET @errors='А воттеперь реально косяк.';
   END

   Реально косяк. Кстати, а что читать?

   akaDElpher, 30 Марта 2011

   Комментарии (2)

9. SQL / Говнокод #6111

   −862

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   SET @SQL = '
         SELECT 
           @diff1 = @diff1 + ''CASE WHEN '' + Field_Name + ''=@'' + Field_Name + 
           '' OR ('' + Field_Name + '' IS null AND @'' + Field_Name + '' IS NULL) THEN ''''''''
     ELSE '''''' + Field_Name + ''="''''+COALESCE(CAST('' + Field_Name + '' AS varchar(max)), ''''NULL'''') 
     + ''''", '''' END +'', 
           @diff2 = @diff2 + ''CASE WHEN '' + Field_Name + ''=@'' + Field_Name + 
           '' OR ('' + Field_Name + '' IS Null AND @'' + Field_Name + '' IS NULL) THEN ''''''''
     ELSE '''''' + Field_Name + ''="''''+COALESCE(CAST(@'' + Field_Name + '' AS varchar(max)), ''''NULL'''')
     + ''''", '''' END +'', 
           @declare = @declare + ''DECLARE @'' + Field_Name +  '' '' + Field_Type + '';'',
           @set = @set + ''SET @'' + Field_Name + ''='' + Field_Value + '';''
           FROM (' + @pre + ') AS t'

   Моё. Кусочек небольшой хранимки в 700 строк.
   
   Формирование SQL-a, который формирует SQL, который, в свою очередь, формирует строку для записи изменений таблицы в лог.

   alter_reserved, 29 Марта 2011

   Комментарии (8)

10. SQL / Говнокод #6105

    −862

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    -- Verify frequency sub-day type
      IF (@freq_subday_type <> 0) AND (@freq_subday_type NOT IN (0x1, 0x2, 0x4, 0x8))
      BEGIN
        RAISERROR(14266, -1, -1, '@freq_subday_type', '0x1, 0x2, 0x4, 0x8')
        RETURN(1) -- Failure
      END
    ....
    
     IF (@freq_subday_type = 0)
        SELECT @freq_subday_type = 0x1 -- FREQSUBTYPE_ONCE
    
      IF ((@freq_subday_type <> 0x1) AND  -- FREQSUBTYPE_ONCE   (see qsched.h)
          (@freq_subday_type <> 0x2) AND  -- FREQSUBTYPE_SECOND (see qsched.h)
          (@freq_subday_type <> 0x4) AND  -- FREQSUBTYPE_MINUTE (see qsched.h)
          (@freq_subday_type <> 0x8))     -- FREQSUBTYPE_HOUR   (see qsched.h)
      BEGIN
        SELECT @reason = FORMATMESSAGE(14266, '@freq_subday_type', '0x1, 0x2, 0x4, 0x8')
        RAISERROR(14278, -1, -1, @reason)
        RETURN(1) -- Failure
      END

    Системная хранимая процедура Microsoft SQL Server 2005
    msdb.[dbo].[sp_verify_schedule]

    alter_reserved, 28 Марта 2011

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