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n = int(input())
d = n
i = 0
a = 0
c = 0
has1 = False
has2 = False
has3 = False
has4 = False
has5 = False
has6 = False
has7 = False
has8 = False
last_dig = 0
while n > 0:
last_dig = n % 10
if last_dig > i :
i = last_dig
if last_dig == 1:
c = 1
elif last_dig == 1:
has1 = True
elif last_dig == 2:
has2 = True
elif last_dig == 3:
has3 = True
elif last_dig == 4:
has4 = True
elif last_dig == 5:
has5 = True
elif last_dig == 6:
has6 = True
elif last_dig == 7:
has7 = True
elif last_dig == 8:
has8 = True
n = n // 10
c = d % 10
if has1 == True and c >= 1:
a = 1
elif has2 == True and c >= 2:
a = 2
elif has3 == True and c >= 3:
a = 3
elif has4 == True and c >= 4:
a = 4
elif has5 == True and c >= 5:
a = 5
elif has6 == True and c >= 6:
a = 6
elif has7 == True and c >= 7:
a = 7
elif has8 == True and c >= 8:
a = 8
else:
a = c
print('Максимальная цифра равна', i)
print('Минимальная цифра равна', a)
Дано натуральное число n. Напишите программу, которая определяет его максимальную и минимальную цифры
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