1. PHP / Говнокод #8657

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    <? include "../o-proekte/connect.php";?>
<ul id="nav">
<li><a class=" link" href="citaty-i-aforizmy/">А</a>
<ul>
<?$a =  iconv('utf8', 'cp1251', "А");
$sql = 'SELECT * FROM authors WHERE name LIKE "'.$a.'%"'; 
$query = mysql_query($sql) or die("Invalid query: " . mysql_error());
While ($row = mysql_fetch_array ($query))
{$results[] = $row;};?>
<? foreach ($results as $num=> $result ) {
echo iconv("cp1251", "utf8", "<li><a href=".$result['id']." id=".$result['name'].">".$result['name']."</a></li>");
}?>
</ul>
</li>
<li><a class=" link" href="citaty-i-aforizmy/">Б</a>
<ul>
<?$b =  iconv('utf8', 'cp1251', "Б");
$sqlb = 'SELECT * FROM authors WHERE name LIKE "'.$b.'%"'; 
$queryb = mysql_query($sqlb) or die("Invalid query: " . mysql_error());
While ($rowb = mysql_fetch_array ($queryb))
{$resultsb[] = $rowb;};?>
<? foreach ($resultsb as $numb=> $resultb ) {
echo iconv("cp1251", "utf8", "<li><a href=\"\">".$resultb['name']."</a></li>");
}?>
</ul>
</li>
<li><a class=" link" href="citaty-i-aforizmy/">В</a>
<ul>
<?$v =  iconv('utf8', 'cp1251', "В");
$sqlv = 'SELECT * FROM authors WHERE name LIKE "'.$v.'%"'; 
$queryv = mysql_query($sqlv) or die("Invalid query: " . mysql_error());
While ($rowv = mysql_fetch_array ($queryv))
{$resultsv[] = $rowv;};?>
<? foreach ($resultsv as $numv=> $resultv ) {
echo iconv("cp1251", "utf8", "<li><a href=\"\">".$resultv['name']."</a></li>");
}?>
</ul>
</li>
<li><a class=" link" href="citaty-i-aforizmy/">Г</a>
<ul>
<?$g =  iconv('utf8', 'cp1251', "Г");
$sqlg = 'SELECT * FROM authors WHERE name LIKE "'.$g.'%"'; 
$queryg = mysql_query($sqlg) or die("Invalid query: " . mysql_error());
While ($rowg = mysql_fetch_array ($queryg))
{$resultsg[] = $rowg;};?>
<? foreach ($resultsg as $numg=> $resultg ) {
echo iconv("cp1251", "utf8", "<li><a href=\"\">".$resultg['name']."</a></li>");
}?>
</ul>
</li>
<li><a class=" link" href="citaty-i-aforizmy/">Д</a>
<ul>
<?$d =  iconv('utf8', 'cp1251', "Д");
$sqld = 'SELECT * FROM authors WHERE name LIKE "'.$d.'%"'; 
$queryd = mysql_query($sqld) or die("Invalid query: " . mysql_error());
While ($rowd = mysql_fetch_array ($queryd))
{$resultsd[] = $rowd;};?>
<? foreach ($resultsd as $numd=> $resultd ) {
echo iconv("cp1251", "utf8", "<li><a href=\"\">".$resultd['name']."</a></li>");
}?>
</ul>
</li>
<li><a class=" link" href="citaty-i-aforizmy/">Е</a>
<ul>
<?$e =  iconv('utf8', 'cp1251', "Е");
$sqle = 'SELECT * FROM authors WHERE name LIKE "'.$e.'%"'; 
$querye = mysql_query($sqle) or die("Invalid query: " . mysql_error());
While ($rowe = mysql_fetch_array ($querye))
{$resultse[] = $rowe;};?>
<? foreach ($resultse as $nume=> $resulte ) {
echo iconv("cp1251", "utf8", "<li><a href=\"\">".$resulte['name']."</a></li>");
}?>
</ul>
</li>
<li><a class=" link" href="citaty-i-aforizmy/">Ж</a>
<ul>
<?$j =  iconv('utf8', 'cp1251', "Ж");
$sqlj = 'SELECT * FROM authors WHERE name LIKE "'.$j.'%"'; 
$queryj = mysql_query($sqlj) or die("Invalid query: " . mysql_error());
While ($rowj = mysql_fetch_array ($queryj))
{$resultsj[] = $rowj;};?>
<? foreach ($resultsj as $numj=> $resultj ) {
echo iconv("cp1251", "utf8", "<li><a href=\"\">".$resultj['name']."</a></li>");
}?>
</ul>
</li>
<li><a class=" link" href="citaty-i-aforizmy/">З</a>
<ul>
<?$z =  iconv('utf8', 'cp1251', "З");
$sqlz = 'SELECT * FROM authors WHERE name LIKE "'.$z.'%"'; 
$queryz = mysql_query($sqlz) or die("Invalid query: " . mysql_error());
While ($rowz = mysql_fetch_array ($queryz))
{$resultsz[] = $rowz;};?>
<? foreach ($resultsz as $numz=> $resultz ) {
echo iconv("cp1251", "utf8", "<li><a href=\"\">".$resultz['name']."</a></li>");

    нужно чтобы php выводил что то типа
    А Б
    август Брайан
    Бекхем
    и т.д. (c)phpforum.ru

    Запостил: hookman, 27 Ноября 2011

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